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20000t^2-1020000t+1000000=0
a = 20000; b = -1020000; c = +1000000;
Δ = b2-4ac
Δ = -10200002-4·20000·1000000
Δ = 960400000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{960400000000}=980000$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1020000)-980000}{2*20000}=\frac{40000}{40000} =1 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1020000)+980000}{2*20000}=\frac{2000000}{40000} =50 $
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